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(4x^2+10)/2=5
We move all terms to the left:
(4x^2+10)/2-(5)=0
We multiply all the terms by the denominator
(4x^2+10)-5*2=0
We add all the numbers together, and all the variables
(4x^2+10)-10=0
We get rid of parentheses
4x^2+10-10=0
We add all the numbers together, and all the variables
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8}=0$
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